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Question

If x is a digit such that the number 18x71¯ is divisible by 3, find possible values of x.

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Solution

It is given that 18x71¯ is a multiple of 3.(1+8+x+7+1) is a multiple of 3.(17+x) is a multiple of 3.17+x=0, 3, 6, 9, 12, 15, 18, 21...But x is a digit. So, x can take values 0,1,2,3,4...9.17+x=18 x=117+x=21 x=417+x=24 x=7x=1,4,7

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