Question

If x is a positive integer such that the distance between points P (x, 2) and Q (3, –­6) is 10 units, then x =

• A. 3
• B. -3
• C. 9
• D. -9

Answer 1

The correct option is C

9

$\sqrt{(3-x{)}^2+(6+2{)}^2}=10$
$(3-x{)}^2+(6+2{)}^2=100$
$(3-x{)}^2=36$
3 - x = ± 6
x = -3 or 9