If x is a positive number and the geometric mean of 9 and 16, find the value of x?

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Solution

The correct option is D 12
x is the geometric mean of 9 and 16. Then we have $9 : x :: x : 16$ are in proportion
$∴$ $x^{2} = 9 \times 16 = 144 x = \sqrt{144} x = \pm 12$

As it is given x is a positive number, geometric mean of 9 and 16 is 12.

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