Question

If x is a real number and $11-2x\le 31$, then find the smallest value of $x$.

• A. 0
• B. -10
• C. 10
• D. -20

Answer 1

The correct option is B -10

$11-2x\le 31$

$-2x\le 31-11$

$-2x\le 20$

$2x\ge -20$

$x\ge \frac{-20}{2}$

$x\ge -10$

Smallest value of $x$ is $-10$