If x is a whole number then $x^{2} (x^{2} - 1)$ is always divisible by

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12 - x

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Multiple of 12

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Solution

The correct option is A 12
Putting x=2, we get $2^{2} (2^{2} - 1) = 12. S o, x^{2} (x^{2} - 1)$ is always divisible by 12

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