If x is less than 4 , x²is less than 16 and x is a natural number. Prove that there are only three values which satisfy all the given equation simultaneously?

Open in App

Solution

Natural numbers are numbers 1,2,3....
for first equation x<4 the natural numbers satisfying this equation is 1,2 and 3
now for the second equation x^2 < 16
the solution of the given equation is -4<x<4 the natural numbers including in this are 1,2&3
so
there are only three values which satisfy all the given equations

Suggest Corrections

Similar questions

If x < 4 , x^2 < 16 and x is a natural number. Prove that there are only three values which satisfy all the given equations simultaneously.

| a |

+ a

a

- a

a

x

| 3 - x | < 4

x

x

x^{2}

If B = {1, 3, 5, 7, 9}, the set-builder representation of B is:

Join BYJU'S Learning Program