The correct option is D 1
As we know,
a=bq+r,0≤r<b
So, we have
x=5q+3 [q is the quotient]
Now, putting x=5q+3 in x2−5x+2, we get
(5q+3)2−5(5q+3)+2
=25q2+9+30q−25q−15+2
=25q2+5q−4
=25q2+5(q+1−1)−4
=25q2+5(q−1)+5−4
=5(5q2+q−1)+1
=5k+1 where k=5q2+q−1
So, remainder is 1.
Hence, correct option is d