If x is nearly equal to 1- then mxm-nxn-m-n-

The correct option is A x^m+n Since x is nearly equal to oneLet x=1+h h lt; lt; lt;1 ——(i)Substituting in the equation we get m ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Ozone

If x is nearl...

Question

If x is nearly equal to 1, then $\frac{m x^{m} - n x^{n}}{m - n} =$

x^{m + n}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{m - n}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{m}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{n}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\frac{x^{m + n} \times x^{n + 1} \times x^{l + m}}{{(x^{m} \times x^{n} \times x^{l})}^{2}} = 1

y = \frac{1}{1 + x^{n - m} + x^{p - m}} + \frac{1}{1 + x^{m - n} + x^{p - n}} + \frac{1}{1 + x^{m - p} + x^{n - p}}, t h e n \frac{d y}{d x}

y = \frac{1}{1 + x^{n - m} + x^{p - m}} + \frac{1}{1 + x^{m - n} + x^{p - n}} + \frac{1}{1 + x^{m - p} + x^{n - p}}

\frac{d y}{d x}

x = e^{m^{n p}}

y = \frac{1}{1 + x^{n - m} + x^{p - m}} + \frac{1}{1 + x^{m - n} + x^{p - n}} + \frac{1}{1 + x^{m - p} + x^{n - p}}

\frac{d y}{d x}

e^{m^{n^{p}}}

The coefficient of $x^{m}$ in $(1 + x)^{m} + (1 + x)^{m + 1} + . . . . . + (1 + x)^{n}$ , m £ n is

Join BYJU'S Learning Program