If x is parallel to y and z, where x=2^i+^j+α^k,y=α^i+^k and z=5^i−^j, then α is equal to
A
±√5
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B
±√6
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C
±√7
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D
None of these
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Solution
The correct option is C±√7 Given, x is parallel to y and z Therefore, x⋅(y×z)=0 ⇒[xyz]=0⇒∣∣
∣∣21αα015−10∣∣
∣∣=0 ⇒2(0+1)−1(0−5)+α(−α−0)=0 ⇒2+5−α2=0 ⇒α2=7 ⇒α=±√7