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Question

If x is parallel to y and z, where x=2^i+^j+α^k,y=α^i+^k and z=5^i^j, then α is equal to

A
±5
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B
±6
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C
±7
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D
None of these
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Solution

The correct option is C ±7
Given, x is parallel to y and z
Therefore, x(y×z)=0
[xyz]=0∣ ∣21αα01510∣ ∣=0
2(0+1)1(05)+α(α0)=0
2+5α2=0
α2=7
α=±7

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