Question

If X is Poisson variate with P(X=0)=P(X=1), then P(X=2)=

• A. $\frac{e}{2}$
• B. $\frac{e}{6}$
• C. $\frac{1}{6e}$
• D. $\frac{1}{2e}$

Answer 1

The correct option is D $\frac{1}{2e}$

$P(x=r)=\frac{e^{-\lambda }{\lambda }^r}{r!}$