Question

If x is positive, the first negative term in the expansion of ${(1+x)}^{\frac{27}{5}}$

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Required term = $\frac{\left(\frac{27}{5}\right)(\frac{27}{5}-1)(\frac{27}{5}-2)\dots \left(\frac{2}{5}\right)-\left(\frac{3}{5}\right)x^7}{7!}\therefore T_8$ is the first negative term.