If x is ratio of rotational kinetic energy and translatroy kinetic energy of rolling body them the following is true
A
x=1
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B
x≤1
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C
x≥1
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D
x=12
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Solution
The correct option is Bx≤1 we know that - Translational kE=12mv2m→ mass v→ velocity Rotational kE=12Iω2=12IR2⋅v2∵(v=Rω)ω→ angular velocity Beccuse moment of Inertia of a uniform Body ⩽mR2 Henu, option (B) is correct.