Question

If x is real and satisfies x + 2 > $\sqrt{x+4}$, then

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Given, x + 2 > $\sqrt{x+4}$ ⇒ $(x+2{)}^2>(x+4)$

⇒$x^2+4x+4>x+4$ ⇒$x^2+3x>0$

⇒ $x(x+3)>0$⇒ $x<-3orx>0$ ⇒ $x>0$