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Question

If x – iy = prove that .

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Solution

The given expression is

xiy= aib cid (1)

On multiplying the numerator and denominator by c+id in R.H.S., we get

xiy= aib cid × c+id c+id = ( ac+bd )+i( adbc ) c 2 + d 2

Now, squaring equation (1), we get

( xiy ) 2 = ( ac+bd )+i( adbc ) c 2 + d 2 x 2 y 2 2ixy= ( ac+bd )+i( adbc ) c 2 + d 2

By comparing the real and imaginary terms, we get

x 2 y 2 = ac+bd c 2 + d 2 ,2xy= adbc c 2 + d 2 (2)

We know that, ( x 2 + y 2 ) 2 = ( x 2 y 2 ) 2 +4 x 2 y 2 [ ( a+b ) 2 = ( ab ) 2 +4ab ]

Solve for ( x 2 + y 2 ) 2 using equation (2)

( x 2 + y 2 ) 2 = ( ac+bd c 2 + d 2 ) 2 + ( adbc c 2 + d 2 ) 2 ( x 2 + y 2 ) 2 = a 2 c 2 + b 2 d 2 +2abcd+ a 2 d 2 + b 2 c 2 2abcd ( c 2 + d 2 ) 2 ( x 2 + y 2 ) 2 = a 2 ( c 2 + d 2 )+ b 2 ( c 2 + d 2 ) ( c 2 + d 2 ) 2

Simplifying the above expression further,

( x 2 + y 2 ) 2 = ( c 2 + d 2 )( a 2 + b 2 ) ( c 2 + d 2 ) 2 ( x 2 + y 2 ) 2 = a 2 + b 2 c 2 + d 2

Hence, proved.


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