If x-i y-a-i b-c-i d- then x2-y22-

The correct option is A nbsp;x+iy=√(a+ib/c+id) ⇒ x iy=√(a ib/c id) Also (x^2+y^2)=(x+iy)(x iy)=√(a^2+b^2/c^2+d^2) ⇒ (x^2+y^2)^2=a^2+b^2/c^2+d^2 ...

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Inequality

If x+i y=√a+i...

Question

If x+iy= $\sqrt{\frac{a + i b}{c + i d}}$ , then $(x^{2} + y^{2})^{2}$ =

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Solution

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Similar questions

x + i y = \sqrt{\frac{a + i b}{c + i d}},

(x^{2} + y^{2})^{2}

$If x + i y = \sqrt{\frac{a + i b}{c + i d}}, then write the value of (x^{2} + y^{2})^{2} .$

x + i y = \sqrt{[\frac{a - i b}{c - i d}]}

(x^{2} + y^{2})^{2} =

x - i y = \sqrt{\frac{a - i b}{c - i d}}

{(x^{2} + y^{2})}^{2} = \frac{a^{2} + b^{2}}{c^{2} + d^{2}}

x + i y = \sqrt{\frac{a + i b}{c + i d}}

(x^{2} + y^{2})^{2} = \frac{a^{2} + b^{2}}{c^{2} + d^{2}}

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