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Question

If xiy=aidcid, prove that (x2+y2)2=a2+b2c2+d2.

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Solution

Here xiy=aidcid

Squaring both sides, we get

(xiy)2=aibcid

|(xiy)2|=aibcid

|xiy||xiy|=|aib||cid|

(x2+y2)(x2+y2)=a2+b2c2+d2

(x2+y2)=a2+b2c2+d2

Squaring both sides

(x2+y2)2=a2+b2c2+d2


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