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Standard XII

Chemistry

Stability of Carbanion

If x K.cal an...

Question

If x K.cal and y K.cals are the $Δ$ H values of ionisation of weak acid (WA) and weak base (WB) respectively, $Δ$ H of neutralisation of the WA and WB is

13.7 K.cal

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-13.7 + (x-y) K.cal

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-13.7 + (x+y) K.cal

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-13.7 - (x+y) K.cal

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Solution

The correct option is C -13.7 + (x+y) K.cal
Weak acid $i o n i s a t i o n - ----- \to H^{P}$ X
Weak base $i o n i s a t i o n - ----- \to O H^{Θ}$ Y
Weak acid + weak base $\to H^{P} + O H^{Θ} \times X Y$
$↓ - 13.75$ K cal
$H_{2} O$
Total $=$ x + y - 13.7 K cal

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Similar questions

The heats of neutralisation of acids $A, B, C$ and $D$ with $N a O H$ are -13.5 K.cal, -12.7 K.cal, -11.8 K.cal, -12.4 K.cal respectively. The weakest acid is:

The heat of combustion of $C H$ $_{4}$ (g), $C$ (graphite) and $H$ $_{4}$ (g) are respectively $- 20 k . c a l$ , $- 40 k . c a l$ and $- 10 k . c a l$ . The heat of formation of CH $_{4}$ is

Δ H_{f} =

-98.2 K.Cal/mole

S_{N a} =

36 K.Cal/mole

I_{N a} =

118.5 K.Cal/mole

\frac{1}{2} D_{C l_{2}} =

29 K.Cal/mole

U_{N a C l} =

-184.2 K.Cal/mole
From the data given below for

N a C l

, the electron affinity of chlorine

[- E_{a}]

is:

Q. Equal volumes of 1 M HNO

_{3}

and 1 M

H_{3} P O_{4}

are neutralised by dilute NaOH solution. If x and y K.cals are the heats liberated in the neutralisation of HNO

_{3}

and

H_{3} P O_{4}

respectively, the relation between x and y (assume

H_{3} P O_{4}

is completely ionised).

The standard heats of formation in K.cal mol $^{- 1}$ of NO $_{2 (g)}$ and N $_{2}$ O $_{4 (g)}$ are 8.0 and 2.0 respectively. The heat of dimerisation of $N O_{2}$ in K.cal is $2 N O_{2 (g)} \to N_{2} O_{4 (g)}$

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If x K.cal and y K.cals are the ΔH values of ionisation of weak acid (WA) and weak base (WB) respectively,ΔH of neutralisation of the WA and WB is

The correct option is C -13.7 + (x+y) K.calWeak acid ionisation−−−−−−→HP XWeak base ionisation−−−−−−→OHΘ YWeak acid + weak base →HP+OHΘ×XY↓−13.75 K calH2OTotal = x + y - 13.7 K cal

If x K.cal and y K.cals are the $Δ$ H values of ionisation of weak acid (WA) and weak base (WB) respectively, $Δ$ H of neutralisation of the WA and WB is

The correct option is C -13.7 + (x+y) K.cal
Weak acid $i o n i s a t i o n - ----- \to H^{P}$ X
Weak base $i o n i s a t i o n - ----- \to O H^{Θ}$ Y
Weak acid + weak base $\to H^{P} + O H^{Θ} \times X Y$
$↓ - 13.75$ K cal
$H_{2} O$
Total $=$ x + y - 13.7 K cal