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Question

If (xāˆ’k) is a common factor of x2+3x+a and x2+4x+b, then find the value of k in terms of a and b.

A
a+b
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B
ab
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C
2a+3b
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D
2a3b
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Solution

The correct option is B ab
Given xk is a common factor of x2+3x+a and x2+4x+b
Therefore,
(k)2+3k+a=0 and (k)2+4k+b=0
k2+4k+b=k2+3k+a
k=ab

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