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Question

If (x+k) is a common factor of (x2+px+q) and (x2+lx+m), then the value of k is ____.

A
l+p
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B
mq
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C
lpmq
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D
mqlp
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Solution

The correct option is D mqlp
Let x2+px+q=0 ....(1)
and x2+lx+m=0 ....(2)
If both equations have the same factor (x+k), then substracting equation (1) from (2), we get
(pl)x+(qm)=0
Common factor is (x+k)
Therefore putting x=k in above equation, we get,
(pl)(k)+(qm)=0k=mqlp

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