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Question

If (x+k) is a factor of the polynomial x22x15 and x2+a. Find k and a.

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Solution

x(k+2)(x+k))¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯x22x15x2+kx________________________(k2)x15(k+2)xk(k+2)___________________________k(k+2)15

(x+k) is a factor of x22x15 and x2+a
k(k+2)15=0
k2+2k15=0
k2+5k3k15=0
k(k+5)3(k+5)=0
k=3or5
if k=3

x3(x+3))¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯x2+a x2+3x_______________3x+a3x9________________9+a
9+a=0
a=9
if k=5

x+5(x5))¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯x2+a x25x_______________5x+a5x25________________25+a
25+a=0
a=25
The solution are
(k,a)=(3,9) and (5,25)

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