If $x = k$ is a solution of the equation $x (2 x + 5) = k$ then the possible values of $x$ is

0

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3

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- 3

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5

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Solution

The correct option is A $0$
$x (2 x + 5) = k$ ............ Given $x = k$
Then $2 x^{2} + 5 x = k$
$2 x^{2} + 5 x - x = 0$
$2 x^{2} + 4 x = 0$
$2 x (x + 2) = 0$
$2 x = 0$ or $x + 2 = 0$
Then $x = 0$ and $x = - 2$

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k

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