Question

If $x=(-\frac{1}{2})$, is a solution of the quadratic equation $3x^2+2kx-3=0$, find the value of k.

Answer 1

As the value $x=-\frac{1}{2}$ satisfies the equation.

Substitute the value into the above equation.

$3x^2+2kx-3=03(-{\frac{1}{2})}^2+2k(-\frac{1}{2})-3=0$

$\frac{3}{4}-k-3=0$

$k=\frac{-9}{4}$