If x=log 0.6; y=log 1.25 and z=log 3−2 log 2, find the values of :
(i) x+y−z
(ii) 5x+y−z
x=log0.6,y=log1.25,z=log3−2log2
z=log3−2log2
z=log3−log22
=log34
=log0.75
(i) x+y−z=log0.6+log1.25+log0.75 0.6× 1.250.75
x+y−z=log0.6× 1.250.75
x+y−z=log1
x+y−z=0
(ii) 5x+y−z = 50 = 1