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Question

If x=log 0.6; y=log 1.25 and z=log 32 log 2, find the values of :

(i) x+yz

(ii) 5x+yz

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Solution

x=log0.6,y=log1.25,z=log32log2

z=log32log2
z=log3log22
=log34
=log0.75

(i) x+yz=log0.6+log1.25+log0.75 0.6× 1.250.75
x+yz=log​​​​​​​0.6× 1.250.75
x+yz=log1
x+yz=0

(ii) 5x+yz​​​​​​​ = 50 = 1


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