If x=logba,y=logcb,z=logac, then xyz is
0
1
2
3
Explanation for the correct option:
Find the value of xyz :
Given,
x=logba,y=logcb,z=logac
We know, logxy=logylogx
So,
xyz=logalogb×logblogc×logcloga=1
Hence, the correct option is B.
If x=logba, y=logcb,z=logac, then xyz is