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Question

If x=loga(bc), y=logb(ca), z=logc(ab), then which of the following is equal to 1

A
x + y + z
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B
(1+x)1+(1+y)1+(1+z)1
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C
xyz
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D
None of these
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Solution

The correct option is B (1+x)1+(1+y)1+(1+z)1
x=logabc1+x=logaa+logabc=logaabc
(1+x)1=logabca
(1+x)1+(1+y)1+(1+z)1=logabc a+logabc c+logabc b
=logabcabc=1

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