If x=loga(bc),y=logb(ca),z=logc(ab),then which of the following is equal to 1
A
x + y + z
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B
(1+x)−1+(1+y)−1+(1+z)−1
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C
xyz
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D
None of these
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Solution
The correct option is B(1+x)−1+(1+y)−1+(1+z)−1 x=logabc⇒1+x=logaa+logabc=logaabc ∴(1+x)−1=logabca ∴(1+x)−1+(1+y)−1+(1+z)−1=logabca+logabcc+logabcb =logabcabc=1