If x- y - -x2 - y2- then calculate the value of 10- -6-

The correct option is B 8 Given x y=√( x ^ 2 y ^ 2 ) Now put x=10 and y= 6 , we get 10 ( 6)=√( 10 ^ 2 ( 6) ^ 2 ) =√(6)4 = 8 ...

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Standard XII

Mathematics

Definition of Relations

If x◊ y = √...

Question

If $x ◊ y = \sqrt{x^{2} - y^{2}}$ , then calculate the value of $10 ◊ (- 6)$ .

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Solution

The correct option is B $8$
Given $x ♢ y = \sqrt{x^{2} - y^{2}}$
Now put $x = 10$ and $y = - 6$ , we get
$10 ♢ (- 6) = \sqrt{10^{2} - {(- 6)}^{2}} = \sqrt{6} 4 = 8$

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If x◊y=√x2−y2, then calculate the value of 10◊(−6).

The correct option is B 8Given x♢y=√x2−y2Now put x=10 and y=−6, we get10♢(−6)=√102−(−6)2=√64=8

If $x ◊ y = \sqrt{x^{2} - y^{2}}$ , then calculate the value of $10 ◊ (- 6)$ .

The correct option is B $8$
Given $x ♢ y = \sqrt{x^{2} - y^{2}}$
Now put $x = 10$ and $y = - 6$ , we get
$10 ♢ (- 6) = \sqrt{10^{2} - {(- 6)}^{2}} = \sqrt{6} 4 = 8$