If $x m o l L^{- 1}$ is the solubility of $K A l (S O_{4})_{2}$ , then $K_{s p}$ is equal to:

x^{3}

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4 x^{4}

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x^{4}

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4 x^{3}

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Solution

The correct option is C $4 x^{4}$
Given that,
Solubility (S) of $K A l (S O_{4})_{2} = x M$

Now,

$K A l (S O_{4})_{2} \to K^{+} x + A l^{3 +} x + 2 S O_{4}^{2 -} 2 x$
$K_{s p} = [K^{+}] [A l^{3 +}] [S O_{4}^{2 -}]^{2}$
$= (x) (x) (2 x)^{2} = 4 x^{4}$ .

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