If $x_{n}$ is a nearer root of equation $f (x) = 0$ , then write the value of $x_{n + 1}$ by Newton-Raphson's method.

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Solution

If $x_{n + 1}$ is a nearer root of the equation $f (x) = 0$ , the value of $x_{n + 1}$ is given by
$x_{n + 1} = x_{n} - \frac{f (x_{n})}{f^{'} (x_{n})}$

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