If x- 0- x-1 2x-1 3x-1 2x 4x-3 6x-3 4x-4 6x-4 8x-4-0- then x-1 is equal to

The correct option is B 0 Given x+1 amp;2x+1 amp;3x+1 2x amp;4x+3 amp;6x+3 4x+4 amp;6x+4 amp;8x+4 #160;=0 ⇒ 2 #160; x ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Properties of Determinants

If x≠ 0, ...

Question

If $x \neq 0$ , $∣ ∣ ∣ ∣ \begin{matrix} x + 1 & 2 x + 1 & 3 x + 1 2 x & 4 x + 3 & 6 x + 3 4 x + 4 & 6 x + 4 & 8 x + 4 \end{matrix} ∣ ∣ ∣ ∣ = 0$ , then $x + 1$ is equal to

x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

x \neq 0

1 + sec x + {sec}^{2} x + {sec}^{3} x + {sec}^{4} x + {sec}^{5} x

f (x)

f (x) = \frac{x}{1 + x} + \frac{x}{(x + 1) (2 x + 1)} + \frac{x}{(2 x + 1) (3 x + 1)} + . . . . . . + \infty

x = 0, f (x)

∣ ∣ ∣ ∣ \begin{matrix} x + 2 & 2 x + 3 & 3 x + 4 2 x + 3 & 3 x + 4 & 4 x + 5 3 x + 5 & 5 x + 8 & 10 x + 17 \end{matrix} ∣ ∣ ∣ ∣ = 0

x

2 (x - 2) + 3 (4 x - 1) = 0

x

(x - 1)^{2} (x + 1)^{3} (x - 4) < 0

Join BYJU'S Learning Program