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Question

If xnπ2 and (cosx)sin2x3sinx+2=1 then all solutions of x are given by

A
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B
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C
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D
None of these
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Solution

The correct option is D None of these
As, xnπ2, we get cosx0,11
So, sin2x3sinx+2=0
sinx=1,2
Which lis not possible as xnπ2
No solution.

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