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Question

If xnπ2 and (cosx)sin2x3sinx+2=1 then all solutions of x are given by


A

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B

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C

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D

None of these

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Solution

The correct option is D

None of these


If xnπ2cosx0,1,1
So sin2x3sinx+2=0
sinx=1,2 which is not possible as xnπ2


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