Question

If $x^o={405}^o$; $y^o=-\frac{{\pi }^o}{12}$, find $x$ and $y$

Answer 1

$x=\frac{\pi }{180}\times 405=\frac{9\pi }{4}$ radius

$y=\frac{\pi }{180}\times \left(\frac{-\pi }{12}\right)=\frac{-{\pi }^2}{2160}$ radians