Question

if $x=p+1$, find the value of $p$ from the equation
$\frac{1}{2}(5x-30)-\frac{1}{3}(1+7p)=\frac{1}{4}$

Answer 1

Given,

$x=p+1.....\left(1\right)$

$\frac{1}{2}(5x-30)-\frac{1}{3}(1+7p)=\frac{1}{4}....\left(2\right)$

Substitute value of $x$ from equation (1) to (2) we get,

$\frac{1}{2}\left(5\right(p+1)-30)-\frac{1}{3}(1+7p)=\frac{1}{4}$

$\frac{1}{2}(5p+5-30)-\frac{1}{3}(1+7p)=\frac{1}{4}$

$\frac{1}{2}(5p-25)-\frac{1}{3}(1+7p)=\frac{1}{4}$

$\frac{3(5p-25)-2(1+7p)}{6}=\frac{1}{4}$

$15p-75-2-14p=\frac{6}{4}$

$p-77=\frac{3}{2}$

$p=77+\frac{3}{2}$

$p=\frac{157}{2}$

or

$p=78.5$