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Question

If xr occurs in the expansion of (x+1x)n, find its coefficient.

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Solution

We can write the expression as xn(1+1x2)n which can be written as xnnp=0 nCp(1x2)np
Coefficient of xn+2p2n is nCp
To find coefficient of xr, put r=n+2p2np=r+n2
The coefficient of xr is nCr+n2

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