If xr occurs in the expansion of (x+1x)n, find its coefficient.
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Solution
We can write the expression as xn(1+1x2)n which can be written as xnn∑p=0nCp(1x2)n−p Coefficient of xn+2p−2n is nCp To find coefficient of xr, put r=n+2p−2n⇒p=r+n2 ∴ The coefficient of xr is nCr+n2