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Question

If x=r sinα cosβ,y=r sinα sinβ and z=rcosα, then

A
x2+y2+z2=r2
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B
x2+y2z2=r2
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C
x2y2+z2=r2
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D
x2+y2z2=r2
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Solution

The correct option is A x2+y2+z2=r2
Given: x=r sinα cosβ,y=r sinα sinβ and z=rcosαx2+y2+z2=r2sin2αcos2β+r2sin2αsin2β+r2cos2α=r2sin2α(cos2β+sin2β)+r2cos2α=r2sin2α+r2cos2α=r2(sin2α+cos2α)=r2

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