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B
x2+y2−z2=r2
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C
x2−y2+z2=r2
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D
x2+y2−z2=r2
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Solution
The correct option is Ax2+y2+z2=r2 Given: x=rsinαcosβ,y=rsinαsinβandz=rcosα∴x2+y2+z2=r2sin2αcos2β+r2sin2αsin2β+r2cos2α=r2sin2α(cos2β+sin2β)+r2cos2α=r2sin2α+r2cos2α=r2(sin2α+cos2α)=r2