CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x=r sinα cosβ,y=r sinα sinβ and z=rcosα, then

A
x2+y2+z2=r2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x2+y2z2=r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2y2+z2=r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x2+y2z2=r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x2+y2+z2=r2
Given: x=r sinα cosβ,y=r sinα sinβ and z=rcosαx2+y2+z2=r2sin2αcos2β+r2sin2αsin2β+r2cos2α=r2sin2α(cos2β+sin2β)+r2cos2α=r2sin2α+r2cos2α=r2(sin2α+cos2α)=r2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Identities_Concept
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon