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Question

If x satisfies the inequality logx+3(x2x)<1, then

A
x(3,2)
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B
x(1,3]
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C
x(1,3)
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D
x(1,0)
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Solution

The correct options are
A x(3,2)
C x(1,3)
D x(1,0)
logx+3(x2x)<1
For the inequality to be defined,
x2x>0 and x+3>0
x(x1)>0 and x>3
x(,0)(1,) and x(3,)
x(3,0)(1,)

Case 1: When x+3>1 i.e., x(2,0)(1,)
x2x<x+3x22x3<0(x3)(x+1)<0x(1,3)
x(1,0)(1,3) (1)

Case 2: When 0<x+3<1 i.e., x(3,2)
x2x>x+3
x22x3>0(x3)(x+1)>0
x(,1)(3,)
x(3,2) (2)

Hence, from (1) and (2),
x(3,2)(1,0)(1,3)

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