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B
x≤−2orx≥4
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C
x≤0orx≥4
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D
−2≤x≤4
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Solution
The correct option is Cx≤0orx≥4 Let(x−1|+(x−2|+(x−3|<6or,((x−1)+(x−2)+(x−3)|<(x−1|+(x−2|+(x−3|<6or,(3x−6|<6or,(x−2|<2or,−2<x−2<2or,0<x<4Hence,for(x−1|+(x−2|+(x−3|≥6,x≤0orx≥4