If x-sec-tan- and y-cosec-cot- then

The correct options are B x=y 1y+1 C y=1+x1 x D xy+x y+1=0 x=secϕ tanϕ and y=cosecϕ+cotϕ ⇒ nbsp;x=1 sinϕ/cosϕ, y=1+cosϕ/sinϕ ...

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Trigonometric Identity- 1

If x=secϕ-t...

Question

If $x = s e c ϕ - t a n ϕ$ and $y = c o s e c ϕ + c o t ϕ$ , then

x = \frac{y + 1}{y - 1}

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x = \frac{y - 1}{y + 1}

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y = \frac{1 + x}{1 - x}

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x y + x - y + 1 = 0

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x = s e c ϕ - t a n ϕ

y = c o s e c ϕ + c o t ϕ

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\frac{1}{5}

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\neq

\neq

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(0 < a < 1, 0 < b < 1)

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x + y \frac{d y}{d x} = 0 (y \neq 0)

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