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Question

If x=sin130o+cos130o then

A
x<0
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B
x=0
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C
x>0
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D
x0
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Solution

The correct option is C x>0
x=sin130+cos130

x=sin(18050)+cos(18050)=sin50cos50

For 45<θ<90,sinθ>cosθ

So sin50>cos50sin50cos50>0x>0


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