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Byju's Answer
Standard XII
Mathematics
Properties Derived from Trigonometric Identities
If x =sin2 ta...
Question
If
x
=
s
i
n
(
2
t
a
n
−
1
2
)
,
y
=
s
i
n
(
1
2
t
a
n
−
1
4
3
)
then
A
x = 1 – y
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B
x
2
=
1
–
y
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C
x
2
=
1
+
y
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D
y
2
=
1
−
x
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Solution
The correct option is
D
y
2
=
1
−
x
Let
t
a
n
−
1
2
=
α
⇒
x
=
s
i
n
2
α
=
4
5
y
=
s
i
n
(
β
2
)
=
√
1
−
c
o
s
β
2
=
√
1
−
3
5
2
=
1
√
5
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1
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