Question

If $x\sin ({90}^0-\theta )\cot ({90}^0-\theta )=\cos ({90}^0-\theta )$, then $x$ is equal to

• A. $0$
• B. $1$
• C. $-1$
• D. $2$

Answer 1

The correct option is B $1$

$xsin({90}^{\circ }-\theta )cot({90}^{\circ }-\theta )=cos({90}^{\circ }-\theta )xcos\theta tan\theta =sin\theta xcos\theta \times \left(\frac{sin\theta }{cos\theta }\right)=sin\theta \therefore x=1$