Question

If $X\sin ({90}^{\circ }-\theta )\cot ({90}^{\circ }-\theta )=\cos (90^{\circ }-\theta )$, then x =

• A. 0
• B. 1
• C. -1
• D. 2

Answer 1

The correct option is B 1

$x\sin (90-\theta )\cot ({90}^o-\theta )=\cos (90-\theta )$

$\Rightarrow x\cos \theta \tan \theta =\sin \theta$

$\Rightarrow x=1$.