If x = √1+√1+√1+.....to infinity, then x =
x = √1+√1+√1+....., to ∞ We have x=√1+x ⇒x2=1+x⇒x2−x−1=0 ⇒x=1±√1+42=1±√52 As x>0, We get x =1+√52
If x = √2+√1, then the value of [x+1x] is ?
If x+1x=3, then the value of x−1x = ?