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Quadratic Formula

If x=√136+√52...

Question

If x = $\sqrt{136 + \sqrt{52 + \sqrt{144}}}$ then value of x equals:

A

12

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B

11

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C

10

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D

13

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Solution

The correct option is A
12

x = $\sqrt{136 + \sqrt{52 + \sqrt{144}}}$

= $\sqrt{136 + \sqrt{64}}$
= $\sqrt{136 + 8}$
= $\sqrt{144} = 12$

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Similar questions

x = \sqrt{136 + \sqrt{52 + \sqrt{144}}}

, then value of

x

\sqrt{1 + \frac{25}{144}} = \frac{x}{12}

\frac{144}{0.144} = \frac{14.4}{x}

, then the value of

x

x^{2} + x + 1 = 0

, then the value of

(x + \frac{1}{x}) + (x^{2} + \frac{1}{x^{2}}) + . . . . + (x^{52} + \frac{1}{x^{52}})

x^{2} + x + 1 = 0

, then the value of

(x + \frac{1}{x}) + (x^{2} + \frac{1}{x^{2}}) + \dots + (x^{52} + \frac{1}{x^{52}})

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