Question

If $x=\sqrt[3]{39},y=\sqrt[4]{411},z=\sqrt[6]{617}$ then _____.

• A. x > y > z
• B. y > z > x
• C. z > y > x
• D. x< y = z

Answer 1

The correct option is A x > y > z

$x=\sqrt[3]{39}$
Taking log in the above equation,
$logx=1/3log9$
$logx=0.32$
$y=\sqrt[4]{411}$
Taking log in the above equation,
$logy=1/4log11$
$logy=0.26$
$z=\sqrt[6]{617}$
Taking log in the above equation,
$logz=1/6log17$
$logz=0.21$
So, we can find out from above value,
x>y>z
Answer (A) x > y > z