Question

If $x=\sqrt{7}-\sqrt{5},y=\sqrt{13}-\sqrt{11}$, then:

• A. $x=y$
• B. $x>y$
• C. $x<y$
• D. $x\ge y$

Answer 1

The correct option is B $x>y$

$x=\sqrt{7}-\sqrt{5}$

$=2.64–2.23=0.41$

$y=\sqrt{13}-\sqrt{11}$

$=3.60-3.31=0.29$

$Hence,x>y$