Question

If x = $\sqrt{a}tan\alpha$ and y = $\sqrt{a}sec\alpha$. Find the value of $y^2$ – $x^2$

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Answer 1

x = $\sqrt{a}tan\alpha$ and y = $\sqrt{a}sec\alpha$

$x^2$ = $ata{n}^2\alpha$ and $y^2$ = $ase{c}^2\alpha$ $\Rightarrow$ $y^2$ - $x^2$ = a$(se{c}^2\alpha -ta{n}^2\alpha )$ = a